Question 5 Find sum of series
S= (a/2!) - (231)+ (2/4). (2151)+
+ (a/10D
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Explanation:
The general terms of the above series can be written as
T
n
=n(n+1)
∴S
n
=Sum of n terms of the series.
=∑T
n
=∑n(n+1)
=∑(n
2
+n)
=∑n
2
+∑n
=
6
n(n+1)(2n+1)
+
2
n(n+1)
=
2
n(n+1)
[
3
2n+1
+1]
=
3
n(n+1)(n+2)
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