Question

The perimeter of a rectangle is 96cm and breadth 20 then length is ?​

Answer 1

Step-by-step explanation:

p = 96cm

b = 20cm

l = ?

perimeter of rectangle = 2 ( l+b )

96 = 2 [ l + 20 ]

96/2 = l + 20

48 = l + 20

l = 48 - 20

l = 28cm

Answer 2

Given: Breadth of a rectangle is 20cm & Perimeter of a rectangle is 96cm.

Need to find: Length of rectangle ?

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❍ Let's consider length of the rectangle be l.

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As we know that,

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$\begin{gathered}\star\:{\underline{\boxed{\frak{Perimeter_{\:(rectangle)} = 2(Length + Breadth)}}}}\\\\\\ \bf{\dag}\:{\underline{\frak{Putting\:given\:values\:in\:formula,}}}\\\\\\ :\implies\sf 96 = 2(l + 20) \\\\\\ :\implies\sf 96 = 2l + 40 \\\\\\ :\implies\sf 2l = 96 - 40\\\\\\ :\implies\sf2l = 56 \\\\\\ :\implies\sf l = \dfrac{56}{2} \\\\\\ :\implies{\underline{\boxed{\frak{\purple{l = 28 }}}}}\:\bigstar\\\\\end{gathered}$

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Therefore,

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Length of rectangular park, l = 28cm.

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$\therefore\:{\underline{\sf{Hence,\:Dimensions\:of\:rectangle\:are\:\bf{20\:cm}\: \sf{and}\: \bf{28\:cm}\: \sf{respectively}.}}}$

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 28 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 20 cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

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★ More to know :

• Area of rectangle = length × breadth
• Diagonal of rectangle = √(length² + breadth²)
• Area of square = side × side
• Perimeter of square = 4 × side
• Diagonal of square = √2 × side