Math, asked by Anonymous, 9 months ago

Question 5 Find the number which bears the smae ratio to 7/33 that 81/21 does to 4/9... No spam plz

Answers

Answered by Anonymous
6

Solution:

Let the required number x/y

Now, ratio of 8/21 to 4/9  = \frac{8/21}{4/9}= 8/21×9/4=6/7

Thus, we have

\frac{x/y}{7/33} = 6/7

=> x/y = \frac{6/7}{7/33}

=> x/y = 6/7 × 7/33

=> x/y = 2/11

Hence, the required number is 2/11.

Answered by ItzDeadDeal
1

Answer:

Solution:

Let the required number x/y

Now, ratio of 8/21 to 4/9 =

 \frac{8/21}{4/9}

= 8/21×9/4=6/7

Thus, we have

\frac{x/y}{7/33} </p><p>

= 6/7

=> x/y =

 \frac{6/7}{7/33}

=> x/y = 6/7 × 7/33

=> x/y = 2/11

Hence, the required number is 2/11.

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