Question

"Question 5 In the given figure, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠BEC = 130° and ∠ECD = 20°. Find ∠BAC.

Class 9 - Math - Circles Page 185"

Answer 1

this is your answer that is 110

Answer 2

Hi friend ✋

Solution--angle CED + angle CEB =180. 【Linear pair}

=angel CED +130°=180°

=angle CED = 180°-130°
=50°
In triangle ECD,angle EDC+angle CED+angle ECD=180°

=angle EDC +50°+20°=180°

=angle EDC =110°

Since angles in the same segment are equal

=angle BAC= angle BDC =110°

Hope it is helpful


Here Tanu【B.s】