"Question 4 In the given figure, ∠ABC = 69°, ∠ACB = 31°, find ∠BDC.
Class 9 - Math - Circles Page 185"
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∠ABC = 69°, ∠ACB = 31° [Given]
In ΔABC
∠ABC + ∠ACB + ∠BAC = 180°
⇒ ∠BAC = 180° - ∠ABC - ∠ACB
⇒ ∠BAC = 180° - 69° - 31° = 80°
∠BDC = ∠BAC ( Angle drawn from same chord)
∴ ∠BDC = 80°
I hope it helps you ^_^
In ΔABC
∠ABC + ∠ACB + ∠BAC = 180°
⇒ ∠BAC = 180° - ∠ABC - ∠ACB
⇒ ∠BAC = 180° - 69° - 31° = 80°
∠BDC = ∠BAC ( Angle drawn from same chord)
∴ ∠BDC = 80°
I hope it helps you ^_^
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This is your answer I.e. is 80
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