Question 5 S and T are point on sides PR and QR of ΔPQR such that ∠P = ∠RTS. Show that ΔRPQ ∼ ΔRTS.
Class 10 - Math - Triangles Page 140
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From ∆RPQ and ∆RTS
< RPQ = <RTS ( given )
<R = <R ( general angle )
.°. ∆RPQ ~ ∆RTS ( criteria of AA )
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< RPQ = <RTS ( given )
<R = <R ( general angle )
.°. ∆RPQ ~ ∆RTS ( criteria of AA )
===================================
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