Question

Question 5 very urgent

Answer 1

First prove ∆PST similar to ∆PRQ:-
angle P. (common)
angle PST and PTS are equal to angle PRQ and PQR respectively. amd then get the ratio of area of ∆PQR and ∆PST which will come out to be 9:49

Now area of trapezium = area of PQR - area of PST
=> 49 - 9 = 40

so now find the ratio of area of ∆ PST to area of trapezium SRQT which will come out to be 9:40

So the final answer is 9:40.