Question

Question 50:
A pressure of 10 Pa acts on an area of 3.0 m2. What is the force acting on the area ? What force will be exerted by the application of same pressure if the area is made one-third ?

Lakhmir Singh Physics Class 9

Answer 1

Answer:

30N , 10N

Explanation:P=F/A i.e.F=PxA   now P=10Pa =10n/m^2 and A=3m^2 so F= 30N

Since area is made 1/3rd so force will be 1/3 of F =10N

Answer 2

Dear Student,

◆ Answer -

F1 = 30 N

F2 = 10 N

● Explanation -

# Given -

P = 10 Pa

A1 = 3 m^2

A2 = 1/3 A1 = 1 m^2

# Solution -

As we know, pressure is given by formula -

P = F1 / A1

F1 = P × A1

F1 = 10 × 3

F1 = 30 N

Later, force is calculated by -

F2 = P × A2

F2 = 10 × 1

F2 = 10 N

Therefore, initial pressure is 30 N and it becomes 10 N if area is 1/3rd.

Hope this helps you...