Question 56:
Given alongside is the velocity-time graph for a moving body :
Find :
(i) Velocity of the body at point C.
(ii) Acceleration acting on the body between A and
(iii) Acceleration acting on the body between B and C.
Lakhmir Singh Physics Class 9
Answers
Hey Dear,
Corresponding diagram is missing from the question. I'll add that in image.
◆ Answers -
- Velocity at C, v = 40 km/h
- Between A and B, a = 6.67 km/h²
- Between B and C, a = 0 km/h²
◆ Explanation -
(i) Velocity of the body at point C -
From the graph, velocity of the body at point C is 40 km/h.
v = 40 km/h
(ii) Acceleration acting on the body between A and B -
a = (v-u)/t
a = (40-20)/3
a = 6.67 km/h²
(iii) Acceleration acting on the body between B and C -
a = (v-u)/t
a = (40-40)/3
a = 0 km/h²
Thanks dear...
Hey friend here is your Answer:
(i) in the given graph the velocity of the body in point C is:
40 km/h
(ii) Acceleration acting on the body between A and B is:
A =(v-u)/t
=(40-20)/3
=20/3
=6.666666667 km/
(iii) Acceleration acting on the body between B and C is:
A =(v-u)/t
=(40-40) / (6-3)
=0/3
=0 km/
please mark me as brainliest.....