Physics, asked by rajracha9473, 11 months ago

Question 56:
Given alongside is the velocity-time graph for a moving body :
Find :
(i) Velocity of the body at point C.
(ii) Acceleration acting on the body between A and
(iii) Acceleration acting on the body between B and C.


Lakhmir Singh Physics Class 9

Answers

Answered by gadakhsanket
66

Hey Dear,

Corresponding diagram is missing from the question. I'll add that in image.

◆ Answers -

  1. Velocity at C, v = 40 km/h
  2. Between A and B, a = 6.67 km/h²
  3. Between B and C, a = 0 km/h²

◆ Explanation -

(i) Velocity of the body at point C -

From the graph, velocity of the body at point C is 40 km/h.

v = 40 km/h

(ii) Acceleration acting on the body between A and B -

a = (v-u)/t

a = (40-20)/3

a = 6.67 km/h²

(iii) Acceleration acting on the body between B and C -

a = (v-u)/t

a = (40-40)/3

a = 0 km/h²

Thanks dear...

Attachments:
Answered by PrafullBadola
14

Hey friend here is your Answer:

(i) in the given graph the velocity of the body in point C is:

  40 km/h

(ii) Acceleration acting on the body between A and B is:

   A =(v-u)/t

      =(40-20)/3

      =20/3

      =6.666666667 km/ h^{2}

(iii) Acceleration acting on the body between B and C is:

    A =(v-u)/t

        =(40-40) / (6-3)

        =0/3

        =0 km/ h^{2}

please mark me as brainliest.....

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