Question 58:
The speed-time graph of an ascending passenger lift is given alongside.
What is the acceleration of the lift:
(i) during the first two seconds ?
(ii) between second and tenth second ?
(iii) during the last two seconds ?
Lakhmir Singh Physics Class 9
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Hello Student,
Corresponding diagram is missing from the question. I'll add that in image.
◆ Answers -
- During first 2 s, a = 2.3 m/s²
- Between 2 s to 10 s, a = 0 m/s²
- In last 2 s, a = -2.3 m/s²
◆ Explanation -
(i) Acceleration during the first two seconds -
a = (v-u)/t
a = (4.6-0)/2
a = 2.3 m/s²
(ii) Acceleration between second and tenth second -
a = (v-u)/t
a = (4.6-4.6)/8
a = 0 m/s²
(iii) Acceleration during the last two seconds -
a = (v-u)/t
a = (0-4.6)/2
a = -2.3 m/s²
Thanks dear...
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