Question

Question. 6
If two adjacent sides of a rectangle are
(5a+3b) and (a-2b) units, its perimeter is
​

Answer 1

Step-by-step explanation:

perimeter of rectangle is 2(l+b)

= 2{(5a+3b)+(a-2b)}

2(5a+3b+a-2b)

2(6a+2b)

12a+4b

Answer 2

Heya Di ❤️⤵️

Perimeter of rectangle = 2(l+b)

=2(5a+3b ) + (a-2b)

=2(5a+3b+a-2b)

=(10a+6b+2a-4b)

=(12a+2b)✔️

Hope , it helps u ✨⚠️