question 6 please if anyone knows
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The solution is in this attachment .Hope it will help you.
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take sec^2(theta) common and you'll be left with,
sec^2(theta){ sec^2(theta) - 1}
we know that,
sec^2(theta) = 1+tan^2(theta)
by using the above identity,
= {1 + tan^2(theta)} {1 + tan^2(theta) - 1}
= [ 1+ tan^2(theta)][tan^2(theta)] ;)
sec^2(theta){ sec^2(theta) - 1}
we know that,
sec^2(theta) = 1+tan^2(theta)
by using the above identity,
= {1 + tan^2(theta)} {1 + tan^2(theta) - 1}
= [ 1+ tan^2(theta)][tan^2(theta)] ;)
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