Question 60:
A ball hits a wall horizontally at 6.0 m s-1. It rebounds horizontally at 4.4 m s-1. The ball is in contact with the wall for 0.040 s. What is the acceleration of the ball ?
Lakhmir Singh Physics Class 9
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Initially velocity = 6m/s ( forward )
Final velocity = 4.4 m/s ( backward ) = -4.4 m/s ( forward )
Acceleration = change in velocity / time
= ( - 4.4 - 6 ) / 0.04 = -10.4/0.04
= -1040/4 = -260 m/s² ( forward )
Final velocity = 4.4 m/s ( backward ) = -4.4 m/s ( forward )
Acceleration = change in velocity / time
= ( - 4.4 - 6 ) / 0.04 = -10.4/0.04
= -1040/4 = -260 m/s² ( forward )
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