Question

question 68 question 68 is a numerical answer question with answer x x x x x.x x

Answer 1

HELLO DEAR,

LET THE THE LADY HAD SAY
Y ONE RUPEES NOTE
AND,
X (20 PAISE COINS)


THE BALANCE WAS
$\frac{1}{3} (y + \frac{x}{5} )$
A TO Q.


$(y + \frac{x}{5} ) - (x + \frac{y}{5} ) = \frac{1}{3} (y + \frac{x}{5} ) \\ = > \frac{4y}{5} - \frac{4x}{5 } = \frac{y}{3} + \frac{x}{15} \\ = > \frac{4y}{5} - \frac{y}{3} = \frac{x}{15} + \frac{4x}{5} \\ = > \frac{7y}{15} = \frac{65x}{75} \\ = > 7y = 13x \\ = > \frac{y}{x} = \frac{13}{7}$

IF WE TAKE ,Y = 13 AND X = 7, THEN ORIGINALLY SHE HAD Rs. 14.40 WITH HER.
ON RETURNING, SHE HAD Rs. 9.60
THE LADY SPENT Rs. 4.80 OR A MULTIPLE OF Rs. 4.80, I.E. Rs. 14.40, WHICH IS ALTERNATIVE


I HOPE ITS HELP YOU DEAR,
THANKS