Question

Question 7.3: A 44 mH inductor is connected to 220 V, 50 Hz ac supply. Determine the rms value of the current in the circuit.

Class 12 - Physics - Alternating Current Alternating Current Page-266

Answer 1

RMS current is given by $I_V=\frac{E_v}{X_L}$
here, $I_v$ is the RMS value of current in circuit.
$E_v$ is the voltage supply by battery e.g., $E_v$=220V
and $X_L$ is the resistance of inductor,
e.g., $X_L=2\pi\nu L$
here v is the frequency and L is inductance of inductor.e.g., XL = 2π × 50 × 44 × 10^-3 ohm

now, Iv = 220/(2π × 50 × 44 × 10^-3) = 15.9A

Answer 2

Hey !!

Given,

           L = 44 mH = 44 × 10⁻³ H , Vrms = 220 V , v = 50 Hz

Inductive reactance of current Xc = ωL

        = Vrms / 2πνL

               = 220 / 2 × ( 22 / 7 ) × 50 × 44 × 10⁻³

                 = 220 × 7 × 10³ / 2 × 22 × 50 × 44

                = 700 / 44

FINAL RESULT = 15.9 A

GOOD LUCK !!