Question

Question 7.31 Dihydrogen gas used in Haber’s process is produced by reacting methane from natural gas with high temperature steam.
The first stage of two stage reaction involves the formation of CO and H2. In second stage, CO formed in first stage is reacted
with more steam in water gas shift reaction,

CO(g) + H2O(g) <---> CO2(g) + H2(g)

If a reaction vessel at 400°C is charged with an equimolar mixture of CO and steam such that pCO = pH2O = 4.0 bar, what will be the partial
pressure of H2 at equilibrium? Kp= 10.1 at 400°C

Class XI Equilibrium Page 228

Answer 1

Hi

Please see the attached file!

Hope it helps you !

Answer 2

CO + H2O <=> CO2 + H2

at t = 0, pressure of CO = 4 bar
Pressure of H2O = 4 bar

at eqlm, pressure of CO = (4 -x)
pressure of H2O =(4- x) bar
pressure of CO2 = x bar
Pressure of H2 = x bar

Now, equilibrium constant (Kc) = [CO2][H2]/[CO][H2O]
Kp = x²/(4 - x)²
10.1 = x²/(4 - x)²
√10.1 = x/(4 - x)
3.17(4 - x) = x
12.68 - 3.17x = x
12.68 = 4.17x
x = 12.68/4.17 = 3.04 bar

hence, pressure of H2 = x bar = 3.04 bar