Question

Question 7.55 Calculate the hydrogen ion concentration in the following biological fluids whose pH are given below:

(a) Human muscle-fluid, 6.83

(b) Human stomach fluid, 1.2

(c) Human blood, 7.38

(d) Human saliva, 6.4.

Class XI Equilibrium Page 229

Answer 1

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Answer 2

(a) pH of human muscle fluid =6.83
.pH = -log[H+]
6.83 = -log[H+], log[H+] = -6.83
log[H+] = -6.83 = 7(bar).17
[H+] = antilog(7(bar).17) = 1.479 * 10⁻⁷ M

(b) pH of stomach fluid = 1.2
pH = -log[H+]
1.2 = -log[H+], log[H+] = -1.2
log[H+] = -1.2 = 2(bar).80
[H+] = antilog(2(bar).80) = 6.31 × 10⁻²M

(c) pH of human blood = 7.38
pH = -log[H+]
-7.38 = log[H+], log[H+] = 8(bar).62
[H+] = antilog(8(bar).62) = 4.169× 10⁻⁸M

(d)pH of human saliva = 6.4
$pH=-log[H^+]\\\\log[H^+]=-6.4=\overline{7}.60$
[H+] = 3.981 × 10⁻⁷M