Question 7.63 Predict if the solutions of the following salts are neutral, acidic or basic:
NaCl, KBr, NaCN, NH4NO3, NaNO2 and KF
Class XI Equilibrium Page 230
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Answered by
11
acidic: NH4NO3 (made with strong acid and weak base).
basic: NaCN, NaNO2, KF(made with strong base and weak acid)
neutral : NaCl ,KBr (made with strong acid and strong base)
i hope it will help you
regards
basic: NaCN, NaNO2, KF(made with strong base and weak acid)
neutral : NaCl ,KBr (made with strong acid and strong base)
i hope it will help you
regards
Answered by
21
The solution of a salt of strong acid and strong base is neutral while that of weak acid and strong base is basic. and A solution of strong acid and a weak base is acidic.
(i) NaCl
NaCl is formed by HCl { strong acid } and NaOH { strong base } . and we know, A solution of strong acid and strong base is neutral.
hence, NaCl is neutral.
(ii) KBr is formed by KOH { strong base } and HBr { strong acid } hence, KBr is neutral.
(iii) NaCN is formed by NaOH { strong base } and HCN { weak acid } hence, NaCN is basic.
(iv) NH4NO3 is formed by HNO3 {strong acid } and NH4OH { weak base } hence , NH4NO3 is acidic.
(v)NaNO2 is formed by NaOH { strong base } and HNO2 { weak acid comparatively} hence, solution is basic.
(vi) KF is formed by KOH { strong base } and HF { weak acid comparatively }
because Hydrolysis of it
F- + H2O <=> HF + OH- , hence, solution is basic.
(i) NaCl
NaCl is formed by HCl { strong acid } and NaOH { strong base } . and we know, A solution of strong acid and strong base is neutral.
hence, NaCl is neutral.
(ii) KBr is formed by KOH { strong base } and HBr { strong acid } hence, KBr is neutral.
(iii) NaCN is formed by NaOH { strong base } and HCN { weak acid } hence, NaCN is basic.
(iv) NH4NO3 is formed by HNO3 {strong acid } and NH4OH { weak base } hence , NH4NO3 is acidic.
(v)NaNO2 is formed by NaOH { strong base } and HNO2 { weak acid comparatively} hence, solution is basic.
(vi) KF is formed by KOH { strong base } and HF { weak acid comparatively }
because Hydrolysis of it
F- + H2O <=> HF + OH- , hence, solution is basic.
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