Question

question 7;8;9 pls answer me

Answer 1

7.First we need context Total number of chips(T) =8
    (a) chance (P.S)=total no. of PS/T=2/8=1/4.
    (b)Similar as (a) chance(M)=3/8
    (c) chance(C.O)=2/8=1/4
     (d)Chance(P)=1/8
8.Total no. of possiblities=6=T
   (a)Since a number is 1 possibilily Chance(3)=1/6
   (b)Chance(<3) =number of num on dice <3/T=2/6=1/3  (∵ 1,2)
   (c)Chance(Even)=number of number on dice even/T=3/6=1/2   (∵2,4,6)
   (d) Chance(7)=0  (∵ On a dice 7 doesnt Exist So it is Impossible to 7)
9.Total no. Marbles =T=14
   (a)Chance (W)=n(w)/T=3/14
   (b)CHance(R)=n(R)/T=5/14
   (c)Chance(B)=n(B)/T=4/14=2/7
   (d)Chance(G)=n(G)/T=2/14=1/7
   (e)CHance(≠W)=n(≠W)/T=11/14
   (f) Chance(≠R)=n(≠R)/T=9/14

Answer 2

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