Question

Question 7 Find the equation of the parabola that satisfies the following conditions: Focus (6, 0); directrix x = –6

Class X1 - Maths -Conic Sections Page 247

Answer 1

concept :- if focus of parabola lies on positive direction of X-axis e.g Focus ( a, 0). and equation of directrix is parallel to Y -axis but cut in negative X - axis .e.g equation of directrix , x = -a then equation of parabola will be of the form , y² = 4ax

Here, Focus ( 6, 0) = ( a , 0)
equation of directrix , x = -6 on comparing with standard equation of direcrix , x = -a .
we get , a = 6

now, equation of parabola
y² = 4ax
y² = 4 × 6 × x
y² = 24x

Answer 2

Step-by-step explanation:

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