Question 7: Find the principal value of sec¯¹(2/√3)
Class 12 - Math - Inverse Trigonometric Functions
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Let −1 ( 2 /√3 ) = ∅, then sec∅ = 2 /√3 = sec( π/6 )
We know that the range of the principal value branch of sec−¹ is [0,π ] − {π /2 }
and sec (π /6 ) = 2 /√3
Therefore, the
principal value of sec-¹ ( 2 /√3 ) is π/6 .
We know that the range of the principal value branch of sec−¹ is [0,π ] − {π /2 }
and sec (π /6 ) = 2 /√3
Therefore, the
principal value of sec-¹ ( 2 /√3 ) is π/6 .
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