Question 8: Find the principal value of cot¯¹(√3)
Class 12 - Math - Inverse Trigonometric Functions
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Answered by
12
x=cot^-1(√3)
cotx= √3
cotx=cot(π/6)
cot^-1 is (0,π)
principal value is π/6
cotx= √3
cotx=cot(π/6)
cot^-1 is (0,π)
principal value is π/6
Answered by
8
Let cot-1√3 = ∅ then cot ∅ = √3 = cot ( π /6 ).
We know that the range of the principal value branch of cot−¹ is (0, π) and cot ( π /6 ) = √3.
Therefore,
the principal value of cot-1√3 is π /6 .
We know that the range of the principal value branch of cot−¹ is (0, π) and cot ( π /6 ) = √3.
Therefore,
the principal value of cot-1√3 is π /6 .
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