"Question 7 Hasan buys two kinds of cloth materials for school uniforms, shirt material that costs him Rs 50 per metre and trouser material that costs him Rs 90 per metre. For every 2 meters of the trouser material he buys 3 metres of the shirt material. He sells the materials at 12% and 10% profit respectively. His total sale is Rs 36660. How much trouser material did he buy?
Linear Equations in One Variable Page 31"
Answers
Equations with linear expressions in one variable only are known as linear equations in one variable.
An algebraic equation is an equality involving variables. It has an equality sign(=). The expression on the left of the equality sign is the Left Hand Side (LHS). The expression on the right of the equality sign is the Right Hand Side (RHS).
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Solution:
Let Hasan bought 2x m of trouser material and 3x m of the shirt material.
Per metre selling price(S.P) of the trouser material = ₹90+90×12/100
= 90 + 1.2× 9
= 90 + 10.8
=₹100.80
Per metre selling price(S.P) of trouser of shirt material
= ₹50+ 50× 10/100
= ₹ 50 + 5
=₹55
Given: total amount of sale= ₹ 36660
100.80 x (2x) + 55 x (3x) = ₹36660
201.60 x + 165x = 36660
366.60 x = 36660
X= 36660/366.60
x = 100
Trouser material = 2x m = (2×100)m = 200m.
Hasan bought 200 m of trouser material.
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Hope this will help you....
Let the length of shirt material purchased be 3x metres and trouser material purchased be 2x metres.
Cost of 1 metre trouser material = ₹90
Cost of 1 metre shirt material = ₹50
(50*112/100)3x +(90*100/100) 2x = 36,600
(560/10)3x +99/10*2x = 36,600
168x +198x = 36,600
366x = 36,600
x = 36,600/366
x = 100 metres
Shirt material = 3x*100=300metres
Trouser material = 2x*100=200metres