Question

question 7 solve please

Answer 1

Answer:

0

Step-by-step explanation:

[IMG}

I hope this helps. :)

Answer 2

$\texttt{Given that}$
${p(x)\:=x^3-x^2+x+1}$

$\texttt{Now when x = 1 or p(1)}$

${= 1^3 - 1^2 + 1 + 1 }$

${= 1 - 1 + 1 + 1}$

${= 2}$


$\texttt{Now when x = -1}$

${={(-1)}^{3} - {(-1)}^{2} + (-1) + 1 }$

${= (-1) -(+1) +(-1) +1 }$

${= -1 -1 -1 + 1}$

${= -2 }$

$\texttt{Now }$

$\frac{p(1) + p(2)}{2} \\ \\ = \frac{2 + ( -2 )}{2} \\ \\ = \frac{2 - 2}{2} \\ \\ = \frac{0}{2}$
$\texttt{Then your Answer is }$
$\texttt{= 0 }$