Question

Question 7 Ten years ago, M was half of N's age. If the ratio of their present ages is 3:4, what will be the total of their present ages? 0 45 O 35 O 40 30​

Answer 1

Option b : 35 is the required answer

$\bf \: Solution$

Let M and N present ages be 3x and 4x respectively.

Ten years ago

M's age was (3x - 10) years ; N's age would be (4x - 10) years

ATQ (According to the question)

M was half of N's age i.e M = N/2

$\sf \: 3x - 10 = \dfrac{4x - 10}{2}$

$\sf \: 6x - 20 = 4x - 10$

$\sf \: 6x - 4x = - 10 + 20$

$\sf \: 2x = 10$

$\bf \: x = 5$

M's present age (3x) = 3*5 = 15 years

N's present age (4x) = 4*5 = 20 years

Total sum of their present ages = 15 + 20 = 35