"Question 7 The inner diameter of a circular well is 3.5 m. It is 10 m deep. Find (i) Its inner curved surface area, (ii) The cost of plastering this curved surface at the rate of Rs 40 per m^2 .
Class 9 - Math - Surface Areas and Volumes Page 217"
Answers
Answered by
5
See the attachment....
Hope it help⛎⛎⛎
Hope it help⛎⛎⛎
Attachments:
Answered by
4
Heya
Here is your answer .
========================================================================
( i ) 2r = 3.5 meter
=> r = 3.5/2 meter
=> r = 1.75 meter
h = 10 meter
.°. Inner curved surface area = 2πrh
= 2 × 22/7 × 1.75 × 10
= 110 meter²
( ii ) The cost of plastering this curved surface at the rate of Rs. 40 per meter² =
110 × 40
= 4400 Rupes.
========================================================================
Here is your answer .
========================================================================
( i ) 2r = 3.5 meter
=> r = 3.5/2 meter
=> r = 1.75 meter
h = 10 meter
.°. Inner curved surface area = 2πrh
= 2 × 22/7 × 1.75 × 10
= 110 meter²
( ii ) The cost of plastering this curved surface at the rate of Rs. 40 per meter² =
110 × 40
= 4400 Rupes.
========================================================================
Similar questions