Question

Question 8.7: The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B0 = 510 nT. What is the amplitude of the electric field part of the wave?

Class 12 - Physics - Electromagnetic Waves Electromagnetic Waves Page-286

Answer 1

amplitude of magnetic field of an electromagnetic wave in a vaccum ,
$B_0=510nT$
speed of light in vacuum,c = 3 × 10^8 m/s
amplitude of electric field of the electromagnetic wave is given by the relation,
$E_0=cB_0=3\times10^8\times510\times10^{-9}\\E_0=153N/C$

therefore electric field part of the wave is 153N/C