Question

question 8) ball thrown from the ground takes 6s to reach the ground find maximum height attained by the ball and the speed with which the ball was thrown upwards take g = 10ms^-2

plz answer it's urgent ​

Answer 1

Answer:

Explanation:

Initial  energy E  

i

​  

=PE+KE=mgh+  

2

1

​  

mv  

2

 

Energy when it reaches the ground: E=  

2

1

​  

mv  

′2

 since PE is zero.

Given, E=  

2

1

​  

E  

i

​  

 

Since it rises to the  same height E  

f

​  

=mgh+0 is the final energy

⇒  

2

1

​  

(mgh+  

2

1

​  

mv  

2

)=E  

f

​  

=mgh+0

v  

2

=2gh=2×10×20=20  

2

 

⇒v=20m/s