question. 8 find the vale of k
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x - 1 = 0 => x = 1
f(x) = f(1) = (1)²- k(1)² + 11(1) - 6 = 1-k+11-6
=> 6-k = 0 => k = 6
f(x) = f(1) = (1)²- k(1)² + 11(1) - 6 = 1-k+11-6
=> 6-k = 0 => k = 6
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