Question 8.
If the product of zeroes of the polynomial ax² - 6x - 6 is 4, find the value of a. Find the sum of
zeroes of the polynomial.
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Answer :
- a = -2/3
- α + β = -9
Solution :
p(x) = ax² - 6x - 6
product of zeroes = 4
c/a = 4
-6/a = 4
a = -2/3
sum of zeroes = -b/a
α + β = 6/(-2/3)
α + β = -9
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