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If α and β are the zeros of the polynomial x2−6x+2 , then (1α+1β)=​

Answer 1

Answer:

6

Step-by-step explanation:

We have a corollary which says,

for a quadratic equation

p(x)=ax²+bx+c

if α and β are zeroes of p(x), then

α+β=(-b/a)

=(-the co-efficient of x/ the co-efficient of x²)

Here,

p(x)=x²-6x+2

So, a=1, b= -6, c=2

(α+β)= -b/a

= -(-6/1)

(α+β)= 6

Cheers!