Question

question 8 pls!!! fast its urgent. it worth 100 points

Answer 1

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Answer 2

Given :

XY || BC = EY || BC

BE || AC = BE || CY

∴ EBCY is a Parallelogram.

Again,

XY || BC = XF || BC

FC || AB = FC || XB

∴ BCFX is a parallelogram.

Now,

||gm EBCY and ||gm BCFX are on the same base BC and between same parallels BC and EF.

∴ Ar(EBCF) = 1 / 2 Area ( BCFX )     ... (i)

Again,

ΔAEB and ||gm EBCY lie on same base BE and between same parallels BE and AC.

∴ Area(ΔABE) = 1 / 2 Area ( EBCY )  ... (ii)

Also,

||gm BCFX and ΔACF on same base and between same parallels CF and AB.

∴ Ar ( ΔACF ) = 1 / 2 Ar ( BCFX )    ... (iii)

Hence,

From (i), (ii) and (iii),

Area of ΔABE = Area of ΔACF.

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