Question

Question 9 Find the value of the trigonometric function sin ( - 11π / 3)

Class X1 - Maths -Trigonometric Functions Page 63

Answer 1

Sin(-11π/3)
[ use sin(-∅) = -sin∅]
= -sin(11π/3)
= -sin(3π + 2π/3)

[ use , sin(n×π + ∅) = -sin∅, where n is odd number]

= -{-sin(2π/3)}
= sin(2π/3)
= sin(π - π/3)

[ use, sin(π-∅) = sin∅]
= sin(π/3)
= sin60°
= √3/2

Answer 2

Step-by-step explanation:

sin [-11π/3}

= √3/2

therefore the trigonometric function of sin[-11/3] is √3/2.