Question :
A body initially at 64 degree celsius cools to 52 degree celsius in 5 minutes , the temperature of surrounding is 16 degree celsius . Find the temperature after further 5 minutes .
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Answer:
In the first case
80- 64
5
=
80+ 64
=
or 3.2 = K [72 – 0,] -...(i) In the second case,
64- 52
5
64+52
*[ 2-00
or 2.4 = K [58 – 0,] ....(ii)
Dividing (i) by (ii), we get
3.2 72-00 2.4 58- 00 or 1856320 = 17282400 or 0, = 16°C
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