Question

• Question
A cube of side 50 mm has its upper face displaced by
0.1 mm w.r.t. lower face by applying a tangential force
of 5 KN. The shear modulus of cube is
3 x 10' N/m2
2x 10' N/m2
1 x 10N/m2
0.5 x 10' N/m2​

Answer 1

Answer:

Shearing modulus of cube η = F lA∆l η = 8 × 103 × 40 ×10- 340 × 10-32 ×0.1 × 10-3 η = 2 × 109 N m-2. · या पानाचे भाषांतर करा