Question: A solution has been prepared by mixing 11.5ml of alcohol with 75.5ml water.Calculate the percentage(by volume) of alcohol in the solution. Please solve with formulae so I can learn it, thanks!
Answers
Answered by
1
Explanation:
percentage of alcohol in solution,=.
=volume of solute ÷ vol of solute + vol of solvent x100
so. % =11.5/11.5+75.5x100
=11.5/87.0x100
=0.1321*100
=13.21%
Similar questions