Question

★Question : -

a wire in the form of square with side 22cm. it is reshaped and bent into the form of circle. calculate the area of this circle.

${ \pink{ \tt{ \maltese \: no \: spam }}}$

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Answer 1

$\huge\colorbox{pink}{Hey mate !}$

$\huge\fbox\green{Given}$

$\sf \: Side \: of \: Square = 22 cm$

$\sf \: Area \: of \: Square = ( side )^2$

$\sf\implies( 22 )^2$

$\sf\implies 484cm^2$

$\small\fbox\pink{Perimeter of square = 4 × side}$

$\sf\implies 4 × 22$

$\sf\implies 88 cm$

$\small\fbox\red{Perimeter of square = Circumference of circle}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \huge\fbox\green{So,}$

$\sf \implies2\pi\:r = 88$

$\sf \implies\:r =\sf\frac{88 \times 7}{2 \times 22}$

$\sf \implies \: r = 14 \: cm$

$\small\fbox\red{Now, area of circle = πr2}$

$\implies \sf \: \frac{22 \times 14 \times 14}{7}$

$\implies \sf616 \: cm {}^{2}$

$\small\fbox\pink{Therefore, Area of circle is 616 \: cm2 }$