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Abdul travelled 300 km by train and 200 km by taxi taking 5 hours 30 minutes. But if he travels to 260 km by train and 240 km by taxi he takes 6 minutes longer. Find the speed of the train and that of the taxi.
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- Abdul travelled 300 km by train and 200 km by taxi taking 5 hours 30 minutes. But if he travels to 260 km by train and 240 km by takes he takes 6 minutes longer. Find the speed of the train and that of the taxi.
- Speed of train = 100km/h
- Speed of taxi = 80km/h
- Abdul travelled 300km by train & 200km by taxi
- Time taken = 5 hours 30 minutes
- Abdul travelled 360km by train & 240km by taxi
- Time taken = 6 min longer
Let the Speed of the train = x km/h
Speed of taxi = y km/h
Case I
Distance covered by train = 300 km
Then
Time taken by train (t1) = 300/x
And
Distance covered by taxi = 200km
So
Time taken by taxi = (t2) = 200/y
Now
➻ t1 + t2 = 5+ (30/60)
➻ 300/x + 200/y = 5+(30/60)
➻ 300/x + 200/y = 11/2____________(1)
Case II
Distance covered by train = 260km
Then
Time taken by train (t3) = 260/x
And
Distance covered by taxi = 240km
Then
Time taken by taxi (t4) = 240/y
➻ t3 + t4 = 5+(36/60)
➻ 260/x + 240/y = 28/5____________(2)
Now
Let 1/x = a , Let 2/y = b
Then
From equation 1 and 2
➻ 300a + 200b = 11/2
➻ 100(3a + 2b) = 11/2
➻ 3a + 2b = 11/200____________(3)
And
➻ 260a + 240b = 28/5
➻ 20(13a + 12b) = 28/5
➻ 13a + 12b = 28/100____________(4)
On multiplying equation 3 by 6
➻ 6(3a + 2b = 11/200)
➻ 18a + 12b = 66/200____________(5)
On Subdtracting equation 4 from 5
18a + 12b = 66/200
13a + 12b = 28/100
- - -
______________________
5a = 66/200 - 26/100
➻ 5a = (66-56)/200
➻ 5a = 10/200
➻ a = 1/20×5
➻ a = 1/100
➻ 1/x = 1/100
➻ x = 100
From equation 3 put a = 1/100
➻ 3/100 + 2b = 11/200
➻ 2b = 11/200-3/100
➻ 2b - 5/200
➻ 2b = 1/40
➻ b = 1/80
➻ 1/y = 1/80
➻ y = 80
- Speed of train = 100km/h
- Speed of taxi = 80km/h
________________________
Hope it's helpful :)
- Abdul travelled 300 km by train and 200 km by taxi taking 5 hours 30 minutes. But if he travels to 260 km by train and 240 km by takes he takes 6 minutes longer. Find the speed of the train and that of the taxi.
- Speed of train = 100km/h
- Speed of taxi = 80km/h
- Abdul travelled 300km by train & 200km by taxi
- Time taken = 5 hours 30 minutes
- Abdul travelled 360km by train & 240km by taxi
- Time taken = 6 min longer
Let the Speed of the train = x km/h
Speed of taxi = y km/h
Case I
Distance covered by train = 300 km
Then
Time taken by train (t1) = 300/x
And
Distance covered by taxi = 200km
So
Time taken by taxi = (t2) = 200/y
Now
➻ t1 + t2 = 5+ (30/60)
➻ 300/x + 200/y = 5+(30/60)
➻ 300/x + 200/y = 11/2____________( 1 )
Case II
Distance covered by train = 260km
Then
Time taken by train (t3) = 260/x
And
Distance covered by taxi = 240km
Then
Time taken by taxi (t4) = 240/y
➻ t3 + t4 = 5+(36/60)
➻ 260/x + 240/y = 28/5____________( 2 )
Now
Let 1/x = a , Let 2/y = b
Then
From equation 1 and 2
➻ 300a + 200b = 11/2
➻ 100(3a + 2b) = 11/2
➻ 3a + 2b = 11/200____________( 3 )
And
➻ 260a + 240b = 28/5
➻ 20(13a + 12b) = 28/5
➻ 13a + 12b = 28/100____________( 4 )
On multiplying equation 3 by 6
➻ 6(3a + 2b = 11/200)
➻ 18a + 12b = 66/200____________( 5 )
On Subdtracting equation 4 from 5
18a + 12b = 66/200
13a + 12b = 28/100
- - -
__________________________
5a = 66/200 - 26/100
➻ 5a = (66-56)/200
➻ 5a = 10/200
➻ a = 1/20×5
➻ a = 1/100
➻ 1/x = 1/100
➻ x = 100
From equation 3 put a = 1/100
➻ 3/100 + 2b = 11/200
➻ 2b = 11/200-3/100
➻ 2b - 5/200
➻ 2b = 1/40
➻ b = 1/80
➻ 1/y = 1/80
➻ y = 80
- Speed of train = 100km/h
- Speed of taxi = 80km/h