Question

Question ↪️

Answer with working. ❌No Copy- paste.❌

Most important = Use inverse trigonometric formulae to differentiate.

Other method will not be accepted. ​

Answer 1

y =sin^-1(2x√(1-x²))

let x= sina

y =sin^-1(2sina.√(1-sin²a))

y =sin^-1(2sina.cosa)

y=sin^-1(sin2a)

y=2a

y=2sin^-1(x)

dy/dx =2.d/dx(sin^-1(x))

=2×1/√(1-x²)

dy/dx =2/√(1-x²)

Answer 2

Here's your solution buddy