Question

question attached in the picture
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Answer 1

Answer:

Let the two balls collide t sec after the first ball is thrown, and let h be the height at which they collide.

For the first ball:

h=40t−

2

1

gt

2

And for the second ball:

h=40(t−2)−

2

1

g(t−2)

2

40t−

2

1

gt

2

=40(t−2)−

2

1

g(t−2)

2

2gt=80+20=100

t=5 sec

∴h=40×5−

2

1

×10×5

2

=75m

Step-by-step explanation:

hope it's helpful to u ;)