Question

Question-
Cyclist starts from rest and acceleration at the rate of 2 metre per second square what will be his velocity after 5 seconds.
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Answer 1

Answer:

10 m/s

Explanation:

$\underline{\bigstar\:\textsf{Given:}}$

Acceleration (a) = 2 m/s²

Initial velocity (u) = 0 m/s

Time (t) = 5 s

$\underline{\bigstar\:\textsf{To\:find:}}$

Final velocity (v) = ?

$\underline{\bigstar\:\textsf{Solution:}}$

Analysis:

There is a cyclist starts from rest accelerates with an acceleration of 2 m/s². Now we have to calculate final velocity of cyclist after 5 seconds.

Let's find now !

If we remember, we have Newton's first law of motion i.e, $\blue{\sf{v\:=\:u\:+\:at}}$

[just put all the given values]

$\longrightarrow$ v = 0 + 2 × 5

$\longrightarrow$ v = 10 m/s

$\sf{\underline{\boxed{\large{\mathsf{\therefore \:Velocity\:is\:10\:m/s}}}}}$

__________________________________

$\underline{\bigstar\:\textsf{Verification:}}$

[put all the values again in the formula]

⟹ 10 = 0 + 2 × 5

⟹ 10 = 0 + 20

⟹ 10 = 10

LHS = RHS. Hence, verified ✔.

Hope it helped you dear...

Answer 2

Answer:

10 m/s

Explanation:

$\underline\pink{\bigstar\:\textsf{Given:}}$

Acceleration (a) = 2 m/s²

Initial velocity (u) = 0 m/s

Time (t) = 5 s

$\underline\pink{\bigstar\:\textsf{To\:find:}}$

Final velocity (v) = ?

$\underline\pink{\bigstar\:\textsf{Solution:}}$

Analysis:

There is a cyclist starts from rest accelerates with an acceleration of 2 m/s². Now we have to calculate final velocity of cyclist after 5 seconds.

Let's find now !

If we remember, we have Newton's first law of motion i.e,

$\color{lime}{\sf{v\:=\:u\:+\:at}}$

[just put all the given values]

$\longrightarrow$ v = 0 + 2 × 5

$\longrightarrow$ v = 10 m/s

$\sf\pink{\underline{\boxed{\large{\mathsf{\therefore \:Velocity\:is\:10\:m/s}}}}}$

__________________________________

$\underline{\bigstar\:\textsf{Verification:}}$

[put all the values again in the formula]

⟹ 10 = 0 + 2 × 5

⟹ 10 = 0 + 20

⟹ 10 = 10

LHS = RHS. Hence, verified ✔.