Question : D and E are respectively the points on the sides AB and AC of
a triangle ABC such that AD = 2 cm, BD = 3 cm, BC = 7.5 cm and DE//BC. Then,
length of DE (in cm) is
(A) 2.5 (B) 3 (C) 5 (D) 6
plzzz give full explanation to this question ur answer should posses similarity of triangles and with proportional sides. and what u have did, how the answer is arrived, everything should be in clear cut explanation answers with half explanation are rejected.and now the time starts...
Answers
Answered by
4
∆BCD=~ ∆DEC (/_DBC=/_DEC,
/_CDE=_BCD,DC=DC ) (BY AAS)
SO BD=DE
DE = 3cm
/_CDE=_BCD,DC=DC ) (BY AAS)
SO BD=DE
DE = 3cm
seenvasreddy:
thanks can u help me in proving this
Answered by
19
Given in triangle ABC, D and E are points on AB and AC
DE is parallel to BC
In triangle ABC, triangle ADE
Therefore
Triangle ABC similar to triangle ADE
DE/BC= AD/AC (ratio of corresponding sides are equal)
DE/7.5=2/5
DE=(2×7.5)/5=15/5=3
DE is parallel to BC
In triangle ABC, triangle ADE
Therefore
Triangle ABC similar to triangle ADE
DE/BC= AD/AC (ratio of corresponding sides are equal)
DE/7.5=2/5
DE=(2×7.5)/5=15/5=3
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