question - factorize : a^3-27
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a^3 - 3^3
aagey identity lage gi
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⇒ a³ – 27
⇒ (a)³ – (3)³
by using formula :
a³ – b³ = (a – b) (a² + ab + b²)
⇒ (a)³ – (3)³
⇒ (a – 3) ( [a]² + a × 3 + [3]²)
⇒ (a – 3) (a² + 3a + 9)
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