Question

Question ➡️➡️
Find the value of ==>
$\sqrt{1} + 3 + 5 + 7 + ... + 19$
Well Elaborated Answers Needed✔️✔️​

Answer 1

Answer:

YOUR ANSWER IS 100

just simply add them ....

we know that √n =n^½ (n, is belong to N)

there for √1 = 1^½ = 1

so, 1+3+5+7..... +19

a= 1 , d=3-1 =2 , an=19

an = a+(n-1)d

=>19= 1+ (n-1)2

=> 19=2n -1

=>n=20/2

=>n=10

Snth = (n/2) [2a + (n-1)d]

S10th = (10/2) [2X1 + (10-1)2]

= (5) [2 + 18]

= 5X 20

= 100

#HOPE IT'S HELPFUL TO U

#BRAINLY