Question

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QUESTION:• For a rever sivale reaction A→B
if initial pressure at 300°c is 1 Atm
and its kp is 4 if then calculate pb.
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Answer 1

$\huge\textbf\green{Answer :}$

$\frac{4}{5}$ $atm.$

$\underline\textbf{Solution :}$

Given :-

$T\:=\:300$°$C$

$P_{A}$ = $1\:atm.$

$K_{P}$ = $4$

$P_{A}$ = $?$

$\textbf{A}$ ----> $\textbf{B}$

$K_{P}$ = $P_{B}$ ÷ $P_{A}$

$P_{B}\:=\:K_{P}$ × $P_{A}$

= $4$ × $1\:atm.$

= $4\:atm.$

Now, Total Pressure = 4 atm. + 1 atm.

= $5\:atm.$

So,

$P_{B}$ = $\frac{4}{5}$ × $1$

= $\frac{4}{5}$ $atm.$

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Answer 2

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Refer to the attachment...!!