Question

question for Aniruddha 31​

Answer 1

$\huge{\boxed{\mathtt{\red{ANSWER}}}}$

let a/2=b/3=c/4 is correct and equal to K

hence,

a/2=b/3=c/4=K

a=2K

b=3K

c=4K

now

b/(a+b)=3K/(2K+3K)=3/5

(a+c-b)/(b+c-a)=(2K+4K-3K)/(3K+4K-2K)

=3/5

(a+b+c)/(2a+b+2c)=(2K+3K+4K)/(4K+3K+8K)

=9K/15K=3/5

here you see,

b/(a+b)=(a+c-b)/(b+c-a)=(a+b+c)/(2a+b+2c)

when ,

a/2=b/3=c/4 is possible .

$<marquee>мαяк ⓐⓢ вяαiηℓisт$

$<marquee>тнαикѕ$

Answer 2

Answer:

hi nandita hope my answer finds you in the pink of your health....

Step-by-step explanation:

i had solved the sum at noon but didn't get the time to post it...

so now i know it's late but still if it favours a bit ...u know..

just see the attachment carefully and understand each line of it..

hope this helps you..

be happy..

keep smiling...

keep raising good questions talented girl..

:))