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♤Maths Aryabhattha♤

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the Radius of a circle is 25 cm and the distance of its chord from the centre is 4 cm what is the length of the chord?​



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Answer 1

Given:-

• The Radius of a circle is 25 cm and the distance of its chord from the centre is 4 cm.

To Assume:-

• The Length of chord

Solution:-

First we have to find the perpendicular

Given,

Radius = 25 cm [AO]

Distance of its chord = 4 cm [BO]

Using Pythagoras Theorem

$\color{hotpink}{AB =\sqrt{ { AO }^{2} - {BO}^{2} }}$

$\color{pink}{[tex]ab = \sqrt{( {25)}^{2} - {(4)}^{2} } </p><p>\\ ab = \sqrt{25 \times 25 - 4 \times 4} </p><p>\\ ab = \sqrt{625 - 16} \\ ab = \sqrt{609} </p><p>$}[/tex]

$\color{purple}{[tex]ab =24.67cm$}[/tex]

Length of the chord :

$length (chord) = 2 \times 24.67 \\ length (chord) = \frac{2467}{1000} \\ length (chord) = \frac{4934}{100} \\ length (chord) =49.34 \: cm$

The Length of the chord is 49.34 cm .

Answer 2

Answer:

Given:-

The Radius of a circle is 25 cm and the distance of its chord from the centre is 4 cm.

To Assume:-

The Length of chord

Solution:-

First we have to find the perpendicular

Given,

Radius = 25 cm [AO]

Distance of its chord = 4 cm [BO]

Using Pythagoras Theorem

Answer 3

Answer:

Given:-

The Radius of a circle is 25 cm and the distance of its chord from the centre is 4 cm.

To Assume:-

The Length of chord

Solution:-

First we have to find the perpendicular

Given,

Radius = 25 cm [AO]

Distance of its chord = 4 cm [BO]

Using Pythagoras Theorem