Math, asked by justinbeiberfan, 1 month ago

Question for Only:- ❏ Moderators ❏ Brainly Stars ❏ Best users ✰ QUESTIONfrom a rectangular cardboard ABCD 2 circles and 1 semicircle of a largest side are cut. calculate the ratio between the area of the remaining cardboard and area of cardboard.​

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Answered by akichanbaby650
2

see your ans from attached pic...

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Answered by kinzal
2

Answer :-

  • For area of remaining cardboard,
  • Area of remaining cardboard = Area of 2 circles + Area of 1 semicircle

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  • Area of Circle = πr²
  • For Area of 2 Circle = 2πr²
  • Area of 1 semicircle =  \sf \frac{1}{2} πr²
  • Area of 1 semicircle =  \sf \frac{πr²}{2}

___________

  • Now,
  • Area of rectangular cupboard = L × b
  • L = r + 2r + 2r = 5r
  • b = 2r
  • Area of rectangular cupboard = L × b
  • Area of rectangular cupboard = ( 5r × 2r )
  • Area of rectangular cupboard = 10 r²

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  • Now,
  • Area of remaining cardboard = Area of rectangular cupboard - ( Area of 2 circles + Area of 1 semicircle )

  • Area of remaining cardboard =  \sf 10r² - \bigg( 2πr² + \frac{πr²}{2} \bigg) \\

  • Area of remaining cardboard =  \sf 10r² - \bigg(\frac{4πr² + πr²}{2} \bigg) \\

  • Area of remaining cardboard =  \sf 10r² - \frac{5πr²}{2} \\

  • Area of remaining cardboard =  \sf  \bigg( \frac{20 {r}^{2} - 5 \frac{22}{7}  {r}^{2}  }{2}  \bigg) \\

  • Area of remaining cardboard =  \sf  \cancel2 \bigg( \frac{10 {r}^{2}  - 5 \times  \frac{11}{7}  {r}^{2}}{ \cancel2}  \bigg) \\

  • Area of remaining cardboard =  \sf \bigg(10 {r}^{2} - 5 \times  \frac{11}{7}  {r}^{2} \bigg) \\

  • Area of remaining cardboard =  \sf \bigg( \frac{70 {r}^{2} - 55 {r}^{2}}{7}  \bigg) \\

  • Area of remaining cardboard =  \sf \bigg( \frac{15 {r}^{2} }{7}  \bigg)

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Now, finally Ratio between the area of the remaining cardboard and area of cardboard.

  • Ratio =  \sf  \frac{the \: \: area \: \:  of \: \: the \: \: remaining \: \: cardboard}{area \: \:  of \: \:  cardboard} \\

  • Ratio =  \sf \frac{\bigg( \frac{15 {r}^{2} }{7}  \bigg)}{10 \: \: r²}\\

  • Ratio =  \sf \frac{15 \cancel{ {r}^{2}} }{7 \times 10 \cancel{ {r}^{2} }} \\

  • Ratio =  \sf \frac{ \cancel5 \times 3}{7 \times  \cancel5 \times 2} \\

  • Ratio =  \sf \frac{3}{14} \\

  • Ratio =  \large \sf {\underline{ 3 : 14 }} \\

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I hope it helps you ❤️✔️

I'm sorry I took too long time to calculate.

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