Math, asked by rs510570, 26 days ago

Two years ago the average age of a family of 8 member was 18 years. After the addition of a boy the average age of the family remains the same today. What is the age of the baby? (a) 2 Years (b) 3 Years (c) 4 Years (d) 2.5 Years​​

Answers

Answered by Anonymous
0

2 Years

Step-by-step explanation:

Average age of 8 members two years ago = 18 years

Sum of age of 8 members two years ago = 144 years

After the addition of a baby the average age of the family is same today.

i.e, Average age of 9 members today = 18 years

Sum of age of 9 member today = 162 years

In these 2 years the age of 8 members is also increased

Increase in the age of 8 members = 8×2 = 16 years

Sum of ages of 8 members today = 144 + 16 = 160 years

Age of child = 162 - 160 = 2 years

Answered by Anonymous
31

Answer:

2

Step-by-step explanation:

Average age of 8 members two years ago = 18 years

Sum of age of 8 members two years ago = 144 years

After the addition of a baby the average age of the family is same today.

i.e, Average age of 9 members today = 18 years

Sum of age of 9 member today = 162 years

In these 2 years the age of 8 members is also increased

Increase in the age of 8 members = 8×2 = 16 years

Sum of ages of 8 members today = 144 + 16 = 160 years

Age of child = 162 - 160 = 2 years

Hope it helps!

Brainliest please! :)

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