Question

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Question for physics expert....

Answer 1

A uniform wire. So resistance of wire between P and M is (2000 / 2) = 1000 ohms 
When the voltmeter is placed in parallel with the wire, the resistance between P and M will be equivalent to 500 ohms. 


(((((1 / Re = 1/1000 + 1 / 1000 
1/Re = 2 / 1000 
Re = 500 ohms )))))


So total resistance between P and Q = (500 + 1000) = 1500 ohms 

Ohm's law: i = v/r
therefore, current entering P = (150 /1500) = 0.1 amp 

Then,voltage across voltmeter = i * Re = (0.1 * 500) = 50 volts

HOPE THIS WILL HELP U... :-)